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By Amir Abboud, Kevin Lewi (auth.), Fedor V. Fomin, Rūsiņš Freivalds, Marta Kwiatkowska, David Peleg (eds.)

This two-volume set of LNCS 7965 and LNCS 7966 constitutes the refereed court cases of the fortieth overseas Colloquium on Automata, Languages and Programming, ICALP 2013, held in Riga, Latvia, in July 2013. the complete of 124 revised complete papers offered have been conscientiously reviewed and chosen from 422 submissions. they're prepared in 3 tracks focussing on algorithms, complexity and video games; common sense, semantics, automata and conception of programming; and foundations of networked computation.

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Analyzing the optimal probability of success directly seems too difficult. Instead, we use the χ2 -divergence to bound the success probability, which turns out to be much more amenable to analysis. From a statistical perspective, the problem of linear sketches of moments can be recast as a minimax statistical estimation problem where one observes the pair (Ax, A) and produces an estimate of x p . More specifically, this is a functional estimation problem, where the goal is to estimation some functional 2 The exact bound is O(1/ 2 ) words; since in this paper we concentrate on the case of = Ω(1) only, we drop dependence on .

Minimizing Maximum (Weighted) Flow-Time 5 23 Lower Bound for Lp Norm of Stretch We show a lower bound for the competitive ratio for the Lp -norm of the stretches, with speed augmentation by a factor of 1 + ε. We assume that there is an online p algorithm with competitive ratio c = o( ε1−3/p ) and derive a contradiction. The construction uses m = 2p machines. We start with the typical construction to get a large load on one machine. For this we consider 2 machines. At time 0 we release two jobs of size 1 (and weight 1) - each can go on exactly one machine.

We now show that the total volume of jobs in S cannot be too large, which leads to a contradiction. Lemma 2. If opt(I) ≤ T , then the total volume of jobs in S is at most I(k,l)∈N (1 + ε)|I(k, l)|. Proof. Suppose opt(I) ≤ T . For an interval Ii (k, l), let Iiε (k, l) be the interval of length (1 + ε)|Ii (k, l)| which starts at the same time as I(k, l). It is easy to check that if I(k , l ) ⊆ I(k, l), then I ε (k , l ) ⊆ I ε (k, l). Let j ∈ S be a job of type (k, l). The off-line optimal solution must schedule it within 2Tk of its release date.

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